1 Try an expression to replace the limit. If you can solve this expression, it is done. This technique works only if the function at x = a. 2 If after the exchange, you can simplify, simplify algebraic first attempt, then substitute. 3 If you get a number for the numerator and the denominator is zero, then no limits. [...] └ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ─ ┘
" So ... that x-> 0, 6 / x ² -> 6 / 0 and is divided by 0) ∞ (or permanent. "
x ^ 2 is always positive, so that is 6 / x ^ 2 is always positive.
The x-> 0 on both sides, the denominator is very small, but the counter remains at 6 The proportion, therefore, is very important - and because it is good that should go to positive infinity.
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ReplyDeleteTechnique to compute: Lim (x-> a) f (x)
1 Try an expression to replace the limit. If you can solve this expression, it is done. This technique works only if the function at x = a.
2 If after the exchange, you can simplify, simplify algebraic first attempt, then substitute.
3 If you get a number for the numerator and the denominator is zero, then no limits.
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"
So ... that x-> 0, 6 / x ² -> 6 / 0
and is divided by 0) ∞ (or permanent.
"
What does that mean?
x ^ 2 is always positive, so that is 6 / x ^ 2 is always positive.
ReplyDeleteThe x-> 0 on both sides, the denominator is very small, but the counter remains at 6 The proportion, therefore, is very important - and because it is good that should go to positive infinity.