Simple Limits Need Help On Limits Its Quick And Simple By I Cant Get The Right Answer?

Need help on Limits its quick and simple by I cant get the right answer? - simple limits

Compute the limit algebraically.

Lim (x-> 0, (-)) 6 / x ^ 2

2 comments:

4th Level Support :p said...

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Technique to compute: Lim (x-> a) f (x)

1 Try an expression to replace the limit. If you can solve this expression, it is done. This technique works only if the function at x = a.
2 If after the exchange, you can simplify, simplify algebraic first attempt, then substitute.
3 If you get a number for the numerator and the denominator is zero, then no limits.
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So ... that x-> 0, 6 / x ² -> 6 / 0
and is divided by 0) ∞ (or permanent.
"

What does that mean?

Steffen said...

x ^ 2 is always positive, so that is 6 / x ^ 2 is always positive.

The x-> 0 on both sides, the denominator is very small, but the counter remains at 6 The proportion, therefore, is very important - and because it is good that should go to positive infinity.

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